Respuesta

B)

Resolviendo obtenemos:

$-0, 25-0, 80\cdot 1,25-\left(\dfrac{-0,75}{\dfrac{3}{4}}\right)=$

$\dfrac{-25}{100} - \dfrac{80}{100} \cdot \dfrac{125}{100} - \left(\dfrac{\dfrac{-75}{100}}{\dfrac{3}{4}}\right)=$

$\dfrac{-1}{4} - \left(\dfrac{8}{10} \cdot \dfrac{5}{4}\right) - \left(\dfrac{-3}{4} \cdot \dfrac{4}{3} \right)=$

$\dfrac{-1}{4} - \left(\dfrac{4}{5} \cdot \dfrac{5}{4}\right) - \left( \dfrac{-12}{12} \right)=$

$\dfrac{-1}{4} - \left(\dfrac{20}{20}\right) +1 =$

$\dfrac{-1}{4} - 1 +1 = \dfrac{-1}{4}$